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x^2+10x-4250=0
a = 1; b = 10; c = -4250;
Δ = b2-4ac
Δ = 102-4·1·(-4250)
Δ = 17100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17100}=\sqrt{900*19}=\sqrt{900}*\sqrt{19}=30\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30\sqrt{19}}{2*1}=\frac{-10-30\sqrt{19}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30\sqrt{19}}{2*1}=\frac{-10+30\sqrt{19}}{2} $
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